x^2+4x=2700

Solution for x^2+4x=2700 equation:

x^2+4x=2700

We move all terms to the left:

x^2+4x-(2700)=0

a = 1; b = 4; c = -2700;
Δ = b2-4ac
Δ = 42-4·1·(-2700)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-104}{2*1}=\frac{-108}{2}
=-54
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+104}{2*1}=\frac{100}{2}
=50
$